-(3/y-6)=-(3/2y-12)+2

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Solution for -(3/y-6)=-(3/2y-12)+2 equation: 



-(3/y-6)=-(3/2y-12)+2

We move all terms to the left:

-(3/y-6)-(-(3/2y-12)+2)=0



Domain of the equation: y-6)!=0

y∈R





Domain of the equation: 2y-12)+2)!=0

y∈R



We get rid of parentheses

-3/y-(-(3/2y-12)+2)+6=0

We calculate fractions


(-6y)/2y^2+(-(-(3*y)/2y^2+6=0

We add all the numbers together, and all the variables

(-6y)/2y^2+(-(-(+3y)/2y^2+6=0

We calculate fractions

We do not support eypression: y^4

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