-(3/2)-(1/3)u=-(3/5)

Solution for -(3/2)-(1/3)u=-(3/5) equation:

-(3/2)-(1/3)u=-(3/5)

We move all terms to the left:

-(3/2)-(1/3)u-(-(3/5))=0


Domain of the equation: 3)u!=0

u!=0/1

u!=0

u∈R


We add all the numbers together, and all the variables

-(+1/3)u-(+3/2)-(-(+3/5))=0

We multiply parentheses

-u^2-(+3/2)-(-(+3/5))=0

We get rid of parentheses

-u^2-3/2-(-(+3/5))=0

We calculate fractions


-u^2+()/()+()/()=0

We add all the numbers together, and all the variables

-1u^2+2=0

a = -1; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-1)·2
Δ = 8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}=2\sqrt{2}$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{2}}{2*-1}=\frac{0-2\sqrt{2}}{-2}
=-\frac{2\sqrt{2}}{-2}
=-\frac{\sqrt{2}}{-1}
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{2}}{2*-1}=\frac{0+2\sqrt{2}}{-2}
=\frac{2\sqrt{2}}{-2}
=\frac{\sqrt{2}}{-1}
$