-(3/2)(1-4x)=9

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Solution for -(3/2)(1-4x)=9 equation: 



-(3/2)(1-4x)=9

We move all terms to the left:

-(3/2)(1-4x)-(9)=0



Domain of the equation: 2)(1-4x)!=0

x∈R



We add all the numbers together, and all the variables

-(+3/2)(-4x+1)-9=0

We multiply parentheses ..

-(-12x^2+3/2*1)-9=0

We multiply all the terms by the denominator


-(-12x^2+3-9*2*1)=0

We get rid of parentheses

12x^2-3+9*2*1=0

We add all the numbers together, and all the variables

12x^2+15=0

a = 12; b = 0; c = +15;
Δ = b2-4ac
Δ = 02-4·12·15
Δ = -720
Delta is less than zero, so there is no solution for the equation

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