-(3/10)(x+1)=10

Solution for -(3/10)(x+1)=10 equation:

-(3/10)(x+1)=10

We move all terms to the left:

-(3/10)(x+1)-(10)=0


Domain of the equation: 10)(x+1)!=0

x∈R


We add all the numbers together, and all the variables

-(+3/10)(x+1)-10=0

We multiply parentheses ..

-(+3x^2+3/10*1)-10=0

We multiply all the terms by the denominator


-(+3x^2+3-10*10*1)=0

We get rid of parentheses

-3x^2-3+10*10*1=0

We add all the numbers together, and all the variables

-3x^2+97=0

a = -3; b = 0; c = +97;
Δ = b2-4ac
Δ = 02-4·(-3)·97
Δ = 1164
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1164}=\sqrt{4*291}=\sqrt{4}*\sqrt{291}=2\sqrt{291}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{291}}{2*-3}=\frac{0-2\sqrt{291}}{-6}
=-\frac{2\sqrt{291}}{-6}
=-\frac{\sqrt{291}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{291}}{2*-3}=\frac{0+2\sqrt{291}}{-6}
=\frac{2\sqrt{291}}{-6}
=\frac{\sqrt{291}}{-3}
$