-(2x-7)+3(4x+1)=5(x-2)

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Solution for -(2x-7)+3(4x+1)=5(x-2) equation: 



-(2x-7)+3(4x+1)=5(x-2)

We move all terms to the left:

-(2x-7)+3(4x+1)-(5(x-2))=0

We multiply parentheses

-(2x-7)+12x-(5(x-2))+3=0

We get rid of parentheses

-2x+12x-(5(x-2))+7+3=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

10x-(5x-10)+10=0

We get rid of parentheses

10x-5x+10+10=0

We add all the numbers together, and all the variables

5x+20=0

We move all terms containing x to the left, all other terms to the right

5x=-20

x=-20/5

x=-4

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