-(2x-5)-(11x-5)+7=-7(x-1)-(9x+8)+3

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Solution for -(2x-5)-(11x-5)+7=-7(x-1)-(9x+8)+3 equation: 



-(2x-5)-(11x-5)+7=-7(x-1)-(9x+8)+3

We move all terms to the left:

-(2x-5)-(11x-5)+7-(-7(x-1)-(9x+8)+3)=0

We get rid of parentheses

-2x-11x-(-7(x-1)-(9x+8)+3)+5+5+7=0



We calculate terms in parentheses: -(-7(x-1)-(9x+8)+3), so:

-7(x-1)-(9x+8)+3

We multiply parentheses

-7x-(9x+8)+7+3

We get rid of parentheses

-7x-9x-8+7+3

We add all the numbers together, and all the variables

-16x+2

Back to the equation:

-(-16x+2)



We add all the numbers together, and all the variables

-13x-(-16x+2)+17=0

We get rid of parentheses

-13x+16x-2+17=0

We add all the numbers together, and all the variables

3x+15=0

We move all terms containing x to the left, all other terms to the right

3x=-15

x=-15/3

x=-5

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