-(2x-4)=+(3x+5)2

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Solution for -(2x-4)=+(3x+5)2 equation: 



-(2x-4)=+(3x+5)2

We move all terms to the left:

-(2x-4)-(+(3x+5)2)=0

We get rid of parentheses

-2x-(+(3x+5)2)+4=0



We calculate terms in parentheses: -(+(3x+5)2), so:

+(3x+5)2

determiningTheFunctionDomain
(3x+5)2

We multiply parentheses

6x+10

Back to the equation:

-(6x+10)



We get rid of parentheses

-2x-6x-10+4=0

We add all the numbers together, and all the variables

-8x-6=0

We move all terms containing x to the left, all other terms to the right

-8x=6

x=6/-8

x=-3/4

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