-(2x-2)=3-(x+2)

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Solution for -(2x-2)=3-(x+2) equation: 



-(2x-2)=3-(x+2)

We move all terms to the left:

-(2x-2)-(3-(x+2))=0

We get rid of parentheses

-2x-(3-(x+2))+2=0



We calculate terms in parentheses: -(3-(x+2)), so:

3-(x+2)

determiningTheFunctionDomain
-(x+2)+3

We get rid of parentheses

-x-2+3

We add all the numbers together, and all the variables

-1x+1

Back to the equation:

-(-1x+1)



We get rid of parentheses

-2x+1x-1+2=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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