-(2x-(3-(4-3x))+6x)=0

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Solution for -(2x-(3-(4-3x))+6x)=0 equation: 



-(2x-(3-(4-3x))+6x)=0

We add all the numbers together, and all the variables

-(2x-(3-(-3x+4))+6x)=0



We calculate terms in parentheses: -(2x-(3-(-3x+4))+6x), so:

2x-(3-(-3x+4))+6x

We add all the numbers together, and all the variables

8x-(3-(-3x+4))



We calculate terms in parentheses: -(3-(-3x+4)), so:

3-(-3x+4)

determiningTheFunctionDomain
-(-3x+4)+3

We get rid of parentheses

3x-4+3

We add all the numbers together, and all the variables

3x-1

Back to the equation:

-(3x-1)



We get rid of parentheses

8x-3x+1

We add all the numbers together, and all the variables

5x+1

Back to the equation:

-(5x+1)



We get rid of parentheses

-5x-1=0

We move all terms containing x to the left, all other terms to the right

-5x=1

x=1/-5

x=-1/5

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