-(2x+2)-3(3x-7)=16

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Solution for -(2x+2)-3(3x-7)=16 equation: 



-(2x+2)-3(3x-7)=16

We move all terms to the left:

-(2x+2)-3(3x-7)-(16)=0

We multiply parentheses

-(2x+2)-9x+21-16=0

We get rid of parentheses

-2x-9x-2+21-16=0

We add all the numbers together, and all the variables

-11x+3=0

We move all terms containing x to the left, all other terms to the right

-11x=-3

x=-3/-11

x=3/11

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