-(2n-4)=2n+4(1-n)

Solution for -(2n-4)=2n+4(1-n) equation:

-(2n-4)=2n+4(1-n)

We move all terms to the left:

-(2n-4)-(2n+4(1-n))=0

We add all the numbers together, and all the variables

-(2n-4)-(2n+4(-1n+1))=0

We get rid of parentheses

-2n-(2n+4(-1n+1))+4=0


We calculate terms in parentheses: -(2n+4(-1n+1)), so:

2n+4(-1n+1)

We multiply parentheses

2n-4n+4

We add all the numbers together, and all the variables

-2n+4

Back to the equation:

-(-2n+4)


We get rid of parentheses

-2n+2n-4+4=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0