-(2n+3)-3(n-5)=27

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Solution for -(2n+3)-3(n-5)=27 equation: 



-(2n+3)-3(n-5)=27

We move all terms to the left:

-(2n+3)-3(n-5)-(27)=0

We multiply parentheses

-(2n+3)-3n+15-27=0

We get rid of parentheses

-2n-3n-3+15-27=0

We add all the numbers together, and all the variables

-5n-15=0

We move all terms containing n to the left, all other terms to the right

-5n=15

n=15/-5

n=-3

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