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-(2/5x)+3=(1/5x)+11
We move all terms to the left:
-(2/5x)+3-((1/5x)+11)=0
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 5x)+11)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+2/5x)-((+1/5x)+11)+3=0
We get rid of parentheses
-2/5x-((+1/5x)+11)+3=0
We calculate fractions
(-10x)/25x^2+(-((+1*5x)/25x^2+3=0
We calculate fractions
We do not support expression: x^4
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