-(2/3)(3x-6)+2=(1/2)(4x-8)

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Solution for -(2/3)(3x-6)+2=(1/2)(4x-8) equation: 



-(2/3)(3x-6)+2=(1/2)(4x-8)

We move all terms to the left:

-(2/3)(3x-6)+2-((1/2)(4x-8))=0



Domain of the equation: 3)(3x-6)!=0

x∈R





Domain of the equation: 2)(4x-8))!=0

x∈R



We add all the numbers together, and all the variables

-(+2/3)(3x-6)-((+1/2)(4x-8))+2=0

We multiply parentheses ..

-(+6x^2+2/3*-6)-((+1/2)(4x-8))+2=0

We calculate fractions


(-(+6x^2+2*2)(4x-8)))/(-6)*2)(4x-8))+3*)+()/(-6)*2)(4x-8))+3*)+2=0

We calculate fractions


((-(+6x^2+2*2)(4x-8)))*(-6)*2)(4x-8))+3*)+2)/((*(-6)*2)(4x-8))+3*)+2)+(-6)*2)(4x-8))+3*)+()*()/((*(-6)*2)(4x-8))+3*)+2)=0

We can not solve this equation

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