-(2+c)-(4+2c)=

Solution for -(2+c)-(4+2c)= equation:

Simplifying
-1(2 + c) + -1(4 + 2c) = 0
(2 * -1 + c * -1) + -1(4 + 2c) = 0
(-2 + -1c) + -1(4 + 2c) = 0
-2 + -1c + (4 * -1 + 2c * -1) = 0
-2 + -1c + (-4 + -2c) = 0

Reorder the terms:
-2 + -4 + -1c + -2c = 0

Combine like terms: -2 + -4 = -6
-6 + -1c + -2c = 0

Combine like terms: -1c + -2c = -3c
-6 + -3c = 0

Solving
-6 + -3c = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + -3c = 0 + 6

Combine like terms: -6 + 6 = 0
0 + -3c = 0 + 6
-3c = 0 + 6

Combine like terms: 0 + 6 = 6
-3c = 6

Divide each side by '-3'.
c = -2

Simplifying
c = -2