-(2+2/5)f=(3+1/5)

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Solution for -(2+2/5)f=(3+1/5) equation: 



-(2+2/5)f=(3+1/5)

We move all terms to the left:

-(2+2/5)f-((3+1/5))=0



Domain of the equation: 5)f!=0

f!=0/1

f!=0

f∈R



We add all the numbers together, and all the variables

-(2/5+2)f-((1/5+3))=0

We multiply parentheses

-2f^2-2f-((1/5+3))=0

We multiply all the terms by the denominator


-2f^2*5+3))-2f*5+3))-((1=0

Wy multiply elements

-10f^2+3))-2f*5+3))-((1=0

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