-(1/6)z=-3.5

Solution for -(1/6)z=-3.5 equation:

-(1/6)z=-3.5

We move all terms to the left:

-(1/6)z-(-3.5)=0


Domain of the equation: 6)z!=0

z!=0/1

z!=0

z∈R


We add all the numbers together, and all the variables

-(+1/6)z-(-3.5)=0

We add all the numbers together, and all the variables

-(+1/6)z+3.5=0

We multiply parentheses

-z^2+3.5=0

We add all the numbers together, and all the variables

-1z^2+3.5=0

a = -1; b = 0; c = +3.5;
Δ = b2-4ac
Δ = 02-4·(-1)·3.5
Δ = 14
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{14}}{2*-1}=\frac{0-\sqrt{14}}{-2}
=-\frac{\sqrt{}}{-2}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{14}}{2*-1}=\frac{0+\sqrt{14}}{-2}
=\frac{\sqrt{}}{-2}
$