-(1/4)a-4=(7/4)a-3

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Solution for -(1/4)a-4=(7/4)a-3 equation: 



-(1/4)a-4=(7/4)a-3

We move all terms to the left:

-(1/4)a-4-((7/4)a-3)=0



Domain of the equation: 4)a!=0

a!=0/1

a!=0

a∈R





Domain of the equation: 4)a-3)!=0

a!=0/1

a!=0

a∈R



We add all the numbers together, and all the variables

-(+1/4)a-((+7/4)a-3)-4=0

We multiply parentheses

-a^2-((+7/4)a-3)-4=0

We multiply all the terms by the denominator


-a^2*4)a-3)-((-4*4)a-3)+7=0

We add all the numbers together, and all the variables

-a^2*4)a-3)-((-16)a-3)+7=0

Wy multiply elements

-4a^3-16)a-3)+7=0

We do not support eapression: a^3

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