-(1/2)(x+4)=16

Solution for -(1/2)(x+4)=16 equation:

-(1/2)(x+4)=16

We move all terms to the left:

-(1/2)(x+4)-(16)=0


Domain of the equation: 2)(x+4)!=0

x∈R


We add all the numbers together, and all the variables

-(+1/2)(x+4)-16=0

We multiply parentheses ..

-(+x^2+1/2*4)-16=0

We multiply all the terms by the denominator


-(+x^2+1-16*2*4)=0

We get rid of parentheses

-x^2-1+16*2*4=0

We add all the numbers together, and all the variables

-1x^2+127=0

a = -1; b = 0; c = +127;
Δ = b2-4ac
Δ = 02-4·(-1)·127
Δ = 508
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{508}=\sqrt{4*127}=\sqrt{4}*\sqrt{127}=2\sqrt{127}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{127}}{2*-1}=\frac{0-2\sqrt{127}}{-2}
=-\frac{2\sqrt{127}}{-2}
=-\frac{\sqrt{127}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{127}}{2*-1}=\frac{0+2\sqrt{127}}{-2}
=\frac{2\sqrt{127}}{-2}
=\frac{\sqrt{127}}{-1}
$