-(1-n)=3(2n-2)

Solution for -(1-n)=3(2n-2) equation:

-(1-n)=3(2n-2)

We move all terms to the left:

-(1-n)-(3(2n-2))=0

We add all the numbers together, and all the variables

-(-1n+1)-(3(2n-2))=0

We get rid of parentheses

1n-(3(2n-2))-1=0


We calculate terms in parentheses: -(3(2n-2)), so:

3(2n-2)

We multiply parentheses

6n-6

Back to the equation:

-(6n-6)


We add all the numbers together, and all the variables

n-(6n-6)-1=0

We get rid of parentheses

n-6n+6-1=0

We add all the numbers together, and all the variables

-5n+5=0

We move all terms containing n to the left, all other terms to the right

-5n=-5

n=-5/-5

n=1