-(1-m)=2(m+2)-5

Solution for -(1-m)=2(m+2)-5 equation:

-(1-m)=2(m+2)-5

We move all terms to the left:

-(1-m)-(2(m+2)-5)=0

We add all the numbers together, and all the variables

-(-1m+1)-(2(m+2)-5)=0

We get rid of parentheses

1m-(2(m+2)-5)-1=0


We calculate terms in parentheses: -(2(m+2)-5), so:

2(m+2)-5

We multiply parentheses

2m+4-5

We add all the numbers together, and all the variables

2m-1

Back to the equation:

-(2m-1)


We add all the numbers together, and all the variables

m-(2m-1)-1=0

We get rid of parentheses

m-2m+1-1=0

We add all the numbers together, and all the variables

-m=0

m=0/-1

m=0