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-(1+7x)-6x(-7+1x)=36
We move all terms to the left:
-(1+7x)-6x(-7+1x)-(36)=0
We add all the numbers together, and all the variables
-(7x+1)-6x(x-7)-36=0
We multiply parentheses
-6x^2-(7x+1)+42x-36=0
We get rid of parentheses
-6x^2-7x+42x-1-36=0
We add all the numbers together, and all the variables
-6x^2+35x-37=0
a = -6; b = 35; c = -37;
Δ = b2-4ac
Δ = 352-4·(-6)·(-37)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{337}}{2*-6}=\frac{-35-\sqrt{337}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{337}}{2*-6}=\frac{-35+\sqrt{337}}{-12} $
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