-(1+3x)=8(x-2)-8x

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Solution for -(1+3x)=8(x-2)-8x equation: 



-(1+3x)=8(x-2)-8x

We move all terms to the left:

-(1+3x)-(8(x-2)-8x)=0

We add all the numbers together, and all the variables

-(3x+1)-(8(x-2)-8x)=0

We get rid of parentheses

-3x-(8(x-2)-8x)-1=0



We calculate terms in parentheses: -(8(x-2)-8x), so:

8(x-2)-8x

We add all the numbers together, and all the variables

-8x+8(x-2)

We multiply parentheses

-8x+8x-16

We add all the numbers together, and all the variables

-16

Back to the equation:

-(-16)



We add all the numbers together, and all the variables

-3x+15=0

We move all terms containing x to the left, all other terms to the right

-3x=-15

x=-15/-3

x=+5

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