-(-8x+3/5)=3/10(-5x-2)

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Solution for -(-8x+3/5)=3/10(-5x-2) equation: 



-(-8x+3/5)=3/10(-5x-2)

We move all terms to the left:

-(-8x+3/5)-(3/10(-5x-2))=0



Domain of the equation: 10(-5x-2))!=0

x∈R



We get rid of parentheses

8x-(3/10(-5x-2))-3/5=0

We calculate fractions


8x+()/(-250x)+(-30x(-)/(-250x)=0



We calculate terms in parentheses: +(-30x(-)/(-250x), so:

-30x(-)/(-250x

We add all the numbers together, and all the variables

-30x0/(-250x

We multiply all the terms by the denominator


-30x0

We add all the numbers together, and all the variables

-30x

Back to the equation:

+(-30x)



We get rid of parentheses

8x+()/(-250x)-30x=0

We multiply all the terms by the denominator


8x*(-250x)-30x*(-250x)+()=0

We add all the numbers together, and all the variables

8x*(-250x)-30x*(-250x)=0

We multiply parentheses

-2000x^2+7500x^2=0

We add all the numbers together, and all the variables

5500x^2=0

a = 5500; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·5500·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{11000}=0$

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