-(-8x+3)=6(x-3)-1

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Solution for -(-8x+3)=6(x-3)-1 equation: 



-(-8x+3)=6(x-3)-1

We move all terms to the left:

-(-8x+3)-(6(x-3)-1)=0

We get rid of parentheses

8x-(6(x-3)-1)-3=0



We calculate terms in parentheses: -(6(x-3)-1), so:

6(x-3)-1

We multiply parentheses

6x-18-1

We add all the numbers together, and all the variables

6x-19

Back to the equation:

-(6x-19)



We get rid of parentheses

8x-6x+19-3=0

We add all the numbers together, and all the variables

2x+16=0

We move all terms containing x to the left, all other terms to the right

2x=-16

x=-16/2

x=-8

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