-(-5-6x)=4x(5x+3)

Solution for -(-5-6x)=4x(5x+3) equation:

-(-5-6x)=4x(5x+3)

We move all terms to the left:

-(-5-6x)-(4x(5x+3))=0

We add all the numbers together, and all the variables

-(-6x-5)-(4x(5x+3))=0

We get rid of parentheses

6x-(4x(5x+3))+5=0


We calculate terms in parentheses: -(4x(5x+3)), so:

4x(5x+3)

We multiply parentheses

20x^2+12x

Back to the equation:

-(20x^2+12x)


We get rid of parentheses

-20x^2+6x-12x+5=0

We add all the numbers together, and all the variables

-20x^2-6x+5=0

a = -20; b = -6; c = +5;
Δ = b2-4ac
Δ = -62-4·(-20)·5
Δ = 436
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{436}=\sqrt{4*109}=\sqrt{4}*\sqrt{109}=2\sqrt{109}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{109}}{2*-20}=\frac{6-2\sqrt{109}}{-40}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{109}}{2*-20}=\frac{6+2\sqrt{109}}{-40}
$