-(-10+8a)=1/2(10-6a)

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Solution for -(-10+8a)=1/2(10-6a) equation: 



-(-10+8a)=1/2(10-6a)

We move all terms to the left:

-(-10+8a)-(1/2(10-6a))=0



Domain of the equation: 2(10-6a))!=0

a∈R



We add all the numbers together, and all the variables

-(8a-10)-(1/2(-6a+10))=0

We get rid of parentheses

-8a-(1/2(-6a+10))+10=0

We multiply all the terms by the denominator


-8a*2(-6a+10))-(1+10*2(-6a+10))=0

Wy multiply elements

-16a^2(-+20a(-=0

We use the square of the difference formula

-16a^2(-20a(-=0

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