,3(2m-1)+5=6(m-1)

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Solution for ,3(2m-1)+5=6(m-1) equation: 



.3(2m-1)+5=6(m-1)

We move all terms to the left:

.3(2m-1)+5-(6(m-1))=0

We multiply parentheses

0.6m-(6(m-1))-0.3+5=0



We calculate terms in parentheses: -(6(m-1)), so:

6(m-1)

We multiply parentheses

6m-6

Back to the equation:

-(6m-6)



We add all the numbers together, and all the variables

0.6m-(6m-6)+4.7=0

We get rid of parentheses

0.6m-6m+6+4.7=0

We add all the numbers together, and all the variables

-5.4m+10.7=0

We move all terms containing m to the left, all other terms to the right

-5.4m=-10.7

m=-10.7/-5.4

m=1+1/1.0188679245283

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