)10=4+3(t+2)

Solution for )10=4+3(t+2) equation:

)10=4+3(t+2)

We move all terms to the left:

)10-(4+3(t+2))=0

We add all the numbers together, and all the variables

-(4+3(t+2))=0


We calculate terms in parentheses: -(4+3(t+2)), so:

4+3(t+2)

determiningTheFunctionDomain
3(t+2)+4

We multiply parentheses

3t+6+4

We add all the numbers together, and all the variables

3t+10

Back to the equation:

-(3t+10)


We get rid of parentheses

-3t-10=0

We move all terms containing t to the left, all other terms to the right

-3t=10

t=10/-3

t=-3+1/3