)-6(3y-5)=18+2y

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Solution for )-6(3y-5)=18+2y equation: 



)-6(3y-5)=18+2y

We move all terms to the left:

)-6(3y-5)-(18+2y)=0

We add all the numbers together, and all the variables

-6(3y-5)-(2y+18)+)=0

We add all the numbers together, and all the variables

-6(3y-5)-(2y+18)=0

We multiply parentheses

-18y-(2y+18)+30=0

We get rid of parentheses

-18y-2y-18+30=0

We add all the numbers together, and all the variables

-20y+12=0

We move all terms containing y to the left, all other terms to the right

-20y=-12

y=-12/-20

y=3/5

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