(z/6)=(6/z)

Solution for (z/6)=(6/z) equation:

(z/6)=(6/z)

We move all terms to the left:

(z/6)-((6/z))=0


Domain of the equation: z))!=0

z!=0/1

z!=0

z∈R


We add all the numbers together, and all the variables

(+z/6)-((+6/z))=0

We get rid of parentheses

z/6-((+6/z))=0

We calculate fractions


z^2/6z+()/6z=0

We multiply all the terms by the denominator


z^2+()=0

We add all the numbers together, and all the variables

z^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{2}=0$