(z/5)=(3/10)+5

Solution for (z/5)=(3/10)+5 equation:

(z/5)=(3/10)+5

We move all terms to the left:

(z/5)-((3/10)+5)=0

We add all the numbers together, and all the variables

(+z/5)-((+3/10)+5)=0

We get rid of parentheses

z/5-((+3/10)+5)=0

We calculate fractions


10z^2/()+()/()=0

We add all the numbers together, and all the variables

10z^2/()+1=0

We multiply all the terms by the denominator


10z^2+1*()=0

We add all the numbers together, and all the variables

10z^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$z=\frac{-b}{2a}=\frac{0}{20}=0$