(z-10)-(10z+6)=2(-8-2z)

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Solution for (z-10)-(10z+6)=2(-8-2z) equation:


Simplifying
(z + -10) + -1(10z + 6) = 2(-8 + -2z)

Reorder the terms:
(-10 + z) + -1(10z + 6) = 2(-8 + -2z)

Remove parenthesis around (-10 + z)
-10 + z + -1(10z + 6) = 2(-8 + -2z)

Reorder the terms:
-10 + z + -1(6 + 10z) = 2(-8 + -2z)
-10 + z + (6 * -1 + 10z * -1) = 2(-8 + -2z)
-10 + z + (-6 + -10z) = 2(-8 + -2z)

Reorder the terms:
-10 + -6 + z + -10z = 2(-8 + -2z)

Combine like terms: -10 + -6 = -16
-16 + z + -10z = 2(-8 + -2z)

Combine like terms: z + -10z = -9z
-16 + -9z = 2(-8 + -2z)
-16 + -9z = (-8 * 2 + -2z * 2)
-16 + -9z = (-16 + -4z)

Add '16' to each side of the equation.
-16 + 16 + -9z = -16 + 16 + -4z

Combine like terms: -16 + 16 = 0
0 + -9z = -16 + 16 + -4z
-9z = -16 + 16 + -4z

Combine like terms: -16 + 16 = 0
-9z = 0 + -4z
-9z = -4z

Solving
-9z = -4z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '4z' to each side of the equation.
-9z + 4z = -4z + 4z

Combine like terms: -9z + 4z = -5z
-5z = -4z + 4z

Combine like terms: -4z + 4z = 0
-5z = 0

Divide each side by '-5'.
z = 0

Simplifying
z = 0

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