(z+6)+(3z-45)=z+40

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Solution for (z+6)+(3z-45)=z+40 equation: 



(z+6)+(3z-45)=z+40

We move all terms to the left:

(z+6)+(3z-45)-(z+40)=0

We get rid of parentheses

z+3z-z+6-45-40=0

We add all the numbers together, and all the variables

3z-79=0

We move all terms containing z to the left, all other terms to the right

3z=79

z=79/3

z=26+1/3

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