(z+2)/3=6

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Solution for (z+2)/3=6 equation: 



(z+2)/3=6

We move all terms to the left:

(z+2)/3-(6)=0

We multiply all the terms by the denominator


(z+2)-6*3=0

We add all the numbers together, and all the variables

(z+2)-18=0

We get rid of parentheses

z+2-18=0

We add all the numbers together, and all the variables

z-16=0

We move all terms containing z to the left, all other terms to the right

z=16

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