(z+2)/(2z+1)=0

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Solution for (z+2)/(2z+1)=0 equation: 



(z+2)/(2z+1)=0



Domain of the equation: (2z+1)!=0

We move all terms containing z to the left, all other terms to the right

2z!=-1

z!=-1/2

z!=-1/2

z∈R



We multiply all the terms by the denominator


(z+2)=0

We get rid of parentheses

z+2=0

We move all terms containing z to the left, all other terms to the right

z=-2

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