(z+2)(z-10)=

Solution for (z+2)(z-10)= equation:

Simplifying
(z + 2)(z + -10) = 0

Reorder the terms:
(2 + z)(z + -10) = 0

Reorder the terms:
(2 + z)(-10 + z) = 0

Multiply (2 + z) * (-10 + z)
(2(-10 + z) + z(-10 + z)) = 0
((-10 * 2 + z * 2) + z(-10 + z)) = 0
((-20 + 2z) + z(-10 + z)) = 0
(-20 + 2z + (-10 * z + z * z)) = 0
(-20 + 2z + (-10z + z2)) = 0

Combine like terms: 2z + -10z = -8z
(-20 + -8z + z2) = 0

Solving
-20 + -8z + z2 = 0

Solving for variable 'z'.

Factor a trinomial.
(-2 + -1z)(10 + -1z) = 0

Subproblem 1
Set the factor '(-2 + -1z)' equal to zero and attempt to solve:

Simplifying
-2 + -1z = 0

Solving
-2 + -1z = 0

Move all terms containing z to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1z = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1z = 0 + 2
-1z = 0 + 2

Combine like terms: 0 + 2 = 2
-1z = 2

Divide each side by '-1'.
z = -2

Simplifying
z = -2
Subproblem 2
Set the factor '(10 + -1z)' equal to zero and attempt to solve:

Simplifying
10 + -1z = 0

Solving
10 + -1z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1z = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1z = 0 + -10
-1z = 0 + -10

Combine like terms: 0 + -10 = -10
-1z = -10

Divide each side by '-1'.
z = 10

Simplifying
z = 10
Solution
z = {-2, 10}