(z+2)(z+4)=

Solution for (z+2)(z+4)= equation:

Simplifying
(z + 2)(z + 4) = 0

Reorder the terms:
(2 + z)(z + 4) = 0

Reorder the terms:
(2 + z)(4 + z) = 0

Multiply (2 + z) * (4 + z)
(2(4 + z) + z(4 + z)) = 0
((4 * 2 + z * 2) + z(4 + z)) = 0
((8 + 2z) + z(4 + z)) = 0
(8 + 2z + (4 * z + z * z)) = 0
(8 + 2z + (4z + z2)) = 0

Combine like terms: 2z + 4z = 6z
(8 + 6z + z2) = 0

Solving
8 + 6z + z2 = 0

Solving for variable 'z'.

Factor a trinomial.
(4 + z)(2 + z) = 0

Subproblem 1
Set the factor '(4 + z)' equal to zero and attempt to solve:

Simplifying
4 + z = 0

Solving
4 + z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + z = 0 + -4

Combine like terms: 4 + -4 = 0
0 + z = 0 + -4
z = 0 + -4

Combine like terms: 0 + -4 = -4
z = -4

Simplifying
z = -4
Subproblem 2
Set the factor '(2 + z)' equal to zero and attempt to solve:

Simplifying
2 + z = 0

Solving
2 + z = 0

Move all terms containing z to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + z = 0 + -2

Combine like terms: 2 + -2 = 0
0 + z = 0 + -2
z = 0 + -2

Combine like terms: 0 + -2 = -2
z = -2

Simplifying
z = -2
Solution
z = {-4, -2}