(z+1)-4(z-4)=5

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Solution for (z+1)-4(z-4)=5 equation:


Simplifying
(z + 1) + -4(z + -4) = 5

Reorder the terms:
(1 + z) + -4(z + -4) = 5

Remove parenthesis around (1 + z)
1 + z + -4(z + -4) = 5

Reorder the terms:
1 + z + -4(-4 + z) = 5
1 + z + (-4 * -4 + z * -4) = 5
1 + z + (16 + -4z) = 5

Reorder the terms:
1 + 16 + z + -4z = 5

Combine like terms: 1 + 16 = 17
17 + z + -4z = 5

Combine like terms: z + -4z = -3z
17 + -3z = 5

Solving
17 + -3z = 5

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-17' to each side of the equation.
17 + -17 + -3z = 5 + -17

Combine like terms: 17 + -17 = 0
0 + -3z = 5 + -17
-3z = 5 + -17

Combine like terms: 5 + -17 = -12
-3z = -12

Divide each side by '-3'.
z = 4

Simplifying
z = 4

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