(z+1)(4i-z)=0

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Solution for (z+1)(4i-z)=0 equation:


Simplifying
(z + 1)(4i + -1z) = 0

Reorder the terms:
(1 + z)(4i + -1z) = 0

Multiply (1 + z) * (4i + -1z)
(1(4i + -1z) + z(4i + -1z)) = 0
((4i * 1 + -1z * 1) + z(4i + -1z)) = 0
((4i + -1z) + z(4i + -1z)) = 0
(4i + -1z + (4i * z + -1z * z)) = 0
(4i + -1z + (4iz + -1z2)) = 0

Reorder the terms:
(4i + 4iz + -1z + -1z2) = 0
(4i + 4iz + -1z + -1z2) = 0

Solving
4i + 4iz + -1z + -1z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add 'z' to each side of the equation.
4i + 4iz + -1z + z + -1z2 = 0 + z

Combine like terms: -1z + z = 0
4i + 4iz + 0 + -1z2 = 0 + z
4i + 4iz + -1z2 = 0 + z
Remove the zero:
4i + 4iz + -1z2 = z

Add 'z2' to each side of the equation.
4i + 4iz + -1z2 + z2 = z + z2

Combine like terms: -1z2 + z2 = 0
4i + 4iz + 0 = z + z2
4i + 4iz = z + z2

Reorder the terms:
4i + 4iz + -1z + -1z2 = z + -1z + z2 + -1z2

Combine like terms: z + -1z = 0
4i + 4iz + -1z + -1z2 = 0 + z2 + -1z2
4i + 4iz + -1z + -1z2 = z2 + -1z2

Combine like terms: z2 + -1z2 = 0
4i + 4iz + -1z + -1z2 = 0

The solution to this equation could not be determined.

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