(y/6)-(y/15)=(1/6)

Solution for (y/6)-(y/15)=(1/6) equation:

(y/6)-(y/15)=(1/6)

We move all terms to the left:

(y/6)-(y/15)-((1/6))=0

We add all the numbers together, and all the variables

(+y/6)-(+y/15)-((+1/6))=0

We get rid of parentheses

y/6-y/15-((+1/6))=0

We calculate fractions


(-216y^2)/()+15y/()+()/()=0

We add all the numbers together, and all the variables

(-216y^2)/()+15y/()+1=0

We multiply all the terms by the denominator


(-216y^2)+15y+1*()=0

We add all the numbers together, and all the variables

(-216y^2)+15y=0

We get rid of parentheses

-216y^2+15y=0

a = -216; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·(-216)·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*-216}=\frac{-30}{-432}
=5/72
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*-216}=\frac{0}{-432}
=0
$