(y/3y-2)-(2/2-3y)

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Solution for (y/3y-2)-(2/2-3y) equation: 


y in (-oo:+oo)

(y/3)*y+3*y-(2/2)-2 = 0

(y/3)*y+3*y-2-1 = 0

1/3*y^2+3*y-3 = 0

DELTA = 3^2-(-3*1/3*4)

DELTA = 13

DELTA > 0

y = (13^(1/2)-3)/(1/3*2) or y = (-13^(1/2)-3)/(1/3*2)

y = 3/2*(13^(1/2)-3) or y = -3/2*(13^(1/2)+3)

y in { -3/2*(13^(1/2)+3), 3/2*(13^(1/2)-3) }

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