(y-4)=-10(y+1/3)

Solution for (y-4)=-10(y+1/3) equation:

(y-4)=-10(y+1/3)

We move all terms to the left:

(y-4)-(-10(y+1/3))=0

We add all the numbers together, and all the variables

(y-4)-(-10(+y+1/3))=0

We get rid of parentheses

y-(-10(+y+1/3))-4=0

We multiply all the terms by the denominator


y*3))-(-10(+y+1-4*3))=0

We add all the numbers together, and all the variables

y*3))-(-10(y-11))=0

We add all the numbers together, and all the variables

y*3))-(-10(y=0

Wy multiply elements

3y^2=0

a = 3; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{6}=0$