(y-4)-7y=5(3y-2)

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Solution for (y-4)-7y=5(3y-2) equation: 



(y-4)-7y=5(3y-2)

We move all terms to the left:

(y-4)-7y-(5(3y-2))=0

We add all the numbers together, and all the variables

-7y+(y-4)-(5(3y-2))=0

We get rid of parentheses

-7y+y-(5(3y-2))-4=0



We calculate terms in parentheses: -(5(3y-2)), so:

5(3y-2)

We multiply parentheses

15y-10

Back to the equation:

-(15y-10)



We add all the numbers together, and all the variables

-6y-(15y-10)-4=0

We get rid of parentheses

-6y-15y+10-4=0

We add all the numbers together, and all the variables

-21y+6=0

We move all terms containing y to the left, all other terms to the right

-21y=-6

y=-6/-21

y=2/7

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