(y-3/y-2)-(y+3/2y)

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Solution for (y-3/y-2)-(y+3/2y) equation: 


D( y )

y = 0

y = 0

y = 0

y in (-oo:0) U (0:+oo)

y-y-((3/2)*y)-(3/y)-2 = 0

y-y+(-3/2)*y-3*y^-1-2 = 0

-3/2*y^1-3*y^-1-2*y^0 = 0

(-3/2*y^2-2*y^1-3*y^0)/(y^1) = 0 // * y^2

y^1*(-3/2*y^2-2*y^1-3*y^0) = 0

y^1

(-3/2)*y^2-2*y-3 = 0

(-3/2)*y^2-2*y-3 = 0

DELTA = (-2)^2-(-3*4*(-3/2))

DELTA = -14

DELTA < 0

y in { } 

y belongs to the empty set

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