(y-2)4y+2=-10

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Solution for (y-2)4y+2=-10 equation: 



(y-2)4y+2=-10

We move all terms to the left:

(y-2)4y+2-(-10)=0

We add all the numbers together, and all the variables

(y-2)4y+12=0

We multiply parentheses

4y^2-8y+12=0

a = 4; b = -8; c = +12;
Δ = b2-4ac
Δ = -82-4·4·12
Δ = -128
Delta is less than zero, so there is no solution for the equation

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