(y-12)(y+4)=0

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Solution for (y-12)(y+4)=0 equation:


Simplifying
(y + -12)(y + 4) = 0

Reorder the terms:
(-12 + y)(y + 4) = 0

Reorder the terms:
(-12 + y)(4 + y) = 0

Multiply (-12 + y) * (4 + y)
(-12(4 + y) + y(4 + y)) = 0
((4 * -12 + y * -12) + y(4 + y)) = 0
((-48 + -12y) + y(4 + y)) = 0
(-48 + -12y + (4 * y + y * y)) = 0
(-48 + -12y + (4y + y2)) = 0

Combine like terms: -12y + 4y = -8y
(-48 + -8y + y2) = 0

Solving
-48 + -8y + y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(-4 + -1y)(12 + -1y) = 0

Subproblem 1

Set the factor '(-4 + -1y)' equal to zero and attempt to solve: Simplifying -4 + -1y = 0 Solving -4 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + -1y = 0 + 4 Combine like terms: -4 + 4 = 0 0 + -1y = 0 + 4 -1y = 0 + 4 Combine like terms: 0 + 4 = 4 -1y = 4 Divide each side by '-1'. y = -4 Simplifying y = -4

Subproblem 2

Set the factor '(12 + -1y)' equal to zero and attempt to solve: Simplifying 12 + -1y = 0 Solving 12 + -1y = 0 Move all terms containing y to the left, all other terms to the right. Add '-12' to each side of the equation. 12 + -12 + -1y = 0 + -12 Combine like terms: 12 + -12 = 0 0 + -1y = 0 + -12 -1y = 0 + -12 Combine like terms: 0 + -12 = -12 -1y = -12 Divide each side by '-1'. y = 12 Simplifying y = 12

Solution

y = {-4, 12}

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