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(y-10)(y/10)=200
We move all terms to the left:
(y-10)(y/10)-(200)=0
We add all the numbers together, and all the variables
(y-10)(+y/10)-200=0
We multiply parentheses ..
(+y^2-10y)-200=0
We get rid of parentheses
y^2-10y-200=0
a = 1; b = -10; c = -200;
Δ = b2-4ac
Δ = -102-4·1·(-200)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-30}{2*1}=\frac{-20}{2} =-10 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+30}{2*1}=\frac{40}{2} =20 $
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