(y-1)/7=(3y-7)/5

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Solution for (y-1)/7=(3y-7)/5 equation: 



(y-1)/7=(3y-7)/5

We move all terms to the left:

(y-1)/7-((3y-7)/5)=0

We calculate fractions


y/()+(-((3y-7)*7)/()=0



We calculate terms in parentheses: +(-((3y-7)*7)/(), so:

-((3y-7)*7)/(

We multiply all the terms by the denominator


-((3y-7)*7)



We calculate terms in parentheses: -((3y-7)*7), so:

(3y-7)*7

We multiply parentheses

21y-49

Back to the equation:

-(21y-49)



We get rid of parentheses

-21y+49

Back to the equation:

+(-21y+49)



We get rid of parentheses

y/()-21y+49=0

We multiply all the terms by the denominator


y-21y*()+49*()=0

We add all the numbers together, and all the variables

y-21y*()=0

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