(y-1)/4=(2y+5)/6

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Solution for (y-1)/4=(2y+5)/6 equation: 



(y-1)/4=(2y+5)/6

We move all terms to the left:

(y-1)/4-((2y+5)/6)=0

We calculate fractions


y/()+(-((2y+5)*4)/()=0



We calculate terms in parentheses: +(-((2y+5)*4)/(), so:

-((2y+5)*4)/(

We multiply all the terms by the denominator


-((2y+5)*4)



We calculate terms in parentheses: -((2y+5)*4), so:

(2y+5)*4

We multiply parentheses

8y+20

Back to the equation:

-(8y+20)



We get rid of parentheses

-8y-20

Back to the equation:

+(-8y-20)



We get rid of parentheses

y/()-8y-20=0

We multiply all the terms by the denominator


y-8y*()-20*()=0

We add all the numbers together, and all the variables

y-8y*()=0

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